Networking Interview Questions
9 Apr, 2007
- In Novell’s use of RIP, there are two metrics used to make routing decisions. Select the two metrics.
* Ticks.
* Hops
* Loops
* Counts
Correct answer: A &B
It first uses ticks (which is about 1/18 sec.); if there is a tie, it uses hops; if hops are equal, then it uses an administratively assigned tiebreaker.
- What is the Cisco name for the encapsulation type used on a serial interface?
* HDLC
* SDLC
* SAP
* SNAP
Correct answer: A
- “arpa” is used by the Cisco IOS for which encapsulation types?
* Ethernet_II
* Ethernet_802.3
* Ethernet_802.2
* Ethernet_SNAP
Correct answer: A
9 Apr, 2007
- Which NetWare protocol provides link-state routing?
* NLSP
* RIP
* SAP
* NCP
Correct answer: A
NetWare Link Services Protocol (NLSP) provides link-state routing. SAP (Service Advertisement Protocol) advertises network services. NCP (NetWare Core Protocol) provides client-to-server connections and applications. RIP is a distance vector routing protocol.
- As a system administrator, you want to debug igrp but are worried that the “debug IP igrp transaction” command will flood the console. What is the command that you should use?
* debug IP igrp event
* debug IP igrp-events
* debug IP igrp summary
* debug IP igrp events
Correct answer: D
The “debug IP igrp events” is used to only display a summary of IGRP routing information. You can append an IP address onto either command to see only the IGRP updates from a neighbor.
9 Apr, 2007
- A default route is analogous to a _________.
* default gateway
* static route
* dynamic route
* one-way route
Correct answer: A
A default route is analogous to a default gateway. It is used to reduce the length of routing tables and to provide complete routing capabilities when a router might not know the routes to all other networks.
9 Apr, 2007
- You are given the following address: 153.50.6.27/25. Determine the subnet mask, address class, subnet address, and broadcast address.
* 255.255.255.128, B,153.50.6.0, 153.50.6.127
* 255.255.255.128, C,153.50.6.0, 153.50.6.127
* 255.255.255.128, C,153.50.6.127, 153.50.6.0
* 255.255.255.224, C,153.50.6.0, 153.50.6.127
Correct answer: A
- You are given the following address: 128.16.32.13/30. Determine the subnet mask, address class, subnet address,
and broadcast address.
* 255.255.255.252, B,128.16.32.12, 128.16.32.15
* 255.255.255.252, C,128.16.32.12, 128.16.32.15
* 255.255.255.252, B,128.16.32.15, 128.16.32.12
* 255.255.255.248, B,128.16.32.12, 128.16.32.15
Correct answer: A
- You are given the following address: 15.16.193.6/21. Determine the subnet mask, address class, subnet address,
and broadcast address.
* 255.255.248.0, A, 15.16.192.0, 15.16.199.255
* 255.255.248.0, B, 15.16.192.0, 15.16.199.255
* 255.255.248.0, A, 15.16.199.255, 14.15.192.0
* 255.255.242.0, A, 15.16.192.0, 15.16.199.255
Correct answer: A
9 Apr, 2007
- Which addresses are INCORRECTLY paired with their class?
* 128 to 191, Class B
* 192 to 223 Class B
* 128 to 191, Class C
* 192 to 223, Class C
Correct answer: B & C
Address classes are: 1 to 126, Class A; 128 to 191, Class B, 192 to 223, Class C; 224 to 239, Class D; and
- to 255, Class E. The first octet rule states that the class of an address can be determined by the numerical value of the first octet.
